An inverted tube barometer is kept on a lift | vedclass

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(A) The lift is moving downward with a deceleration $\alpha$. This means the net acceleration of the lift is directed upward.The effective acceleratio

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Height of the mercury column in the lift will be $\frac{P_0}{\rho(g + \alpha)}$

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(A) The lift is moving downward with a deceleration $\alpha$. This means the net acceleration of the lift is directed upward.The effective acceleration due to gravity $g_{eff}$ in the frame of the lift is given by $g_{eff} = g + a$,where $a$ is the magnitude of the deceleration.In a barometer,the atmospheric pressure $P_0$ is balanced by the pressure exerted by the mercury column of height $h$,which is given by $P = \rho g_{eff} h$.Equating the two,we get $P_0 = \rho (g + \alpha) h$.Solving for $h$,we get $h = \frac{P_0}{\rho (g + \alpha)}$.

An inverted tube barometer is kept on a lift moving downward with a deceleration $\alpha$. The density of mercury is $\rho$ and the acceleration due to gravity is $g$. If the atmospheric pressure is $P_0$,then:

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